Simplify
(2a^2b^3z^3)/(8ab^2z^4)
2007-02-26 11:34:53 · 6 answers · asked by balla24n7 2 in Education & Reference ➔ Homework Help
Because you don't have to worry about addition or subtraction, you can cancel out the common bases. It might be easier to break it down.
(2/8)(a^2/a)(b^3/b^2)(z^3/z^4)
(1/4)(a/1)(b/1)(1/z)
(ab/4z)
2007-02-27 04:29:10 · answer #1 · answered by raegirl22 5 · 2⤊ 0⤋
When dividing exponents with the same base, you keep the base and subtract the exponents. The 2/8 is reduced as for all fractions and you get 1/4. a^2/a = a.....b^3/b2= b...z^3/z^4 = z^-1 which is a fraction. Put it all together and you get ab/4z.
2007-02-26 12:25:34 · answer #2 · answered by dpirsq2 5 · 0⤊ 0⤋
when its dividing you subtract the common variables in the denominator from the numerator.
(2/8)(a^2-1)(b^3-2)(z^3-4)=
(1/4)(a^1)(b^1)(z^-1)
since z is to the -1 power it moves to the denominator so the answer simplified would be:
(ab)
------
(4z)
2007-02-26 11:48:56 · answer #3 · answered by Anonymous · 0⤊ 0⤋
36abz / 64abz = [9 / 16]
I couldn't fully understand your equation
2007-02-26 11:50:10 · answer #4 · answered by LifeOfSeer 1 · 0⤊ 0⤋
(2a^2b^3z^3)/(8ab^2z^4)
(ab)/(4z)
2007-02-26 11:42:19 · answer #5 · answered by Bhajun Singh 4 · 0⤊ 0⤋
I don't want to!
2007-02-26 11:42:16 · answer #6 · answered by Natalie M 3 · 0⤊ 0⤋