An air filled balloon will float very high on the water. A weight tied to it will make it float lower or even make in sink. Suppose you attach a weight to an air filled balloon that puts it at the verge of sinking - that is the overall density of the weight and balloon is equal to that of the water and its top surface just touches the water line. Now, if you push the balloon beneath the surface of the water what will the balloon do? Explain.
2007-02-26 11:02:21 · 2 answers · asked by jonoco 1 in Science & Mathematics ➔ Physics
if the density is equal to that of the water it will remain where you placed it....hence the reason why submarines don't sink to the bottom.
2007-02-26 11:12:44 · answer #1 · answered by The Cheminator 5 · 0⤊ 0⤋
Before you push it, it stays where it is. As soon as you push it, it goes down as long as you are pushing. Then again it will be suspended where it is. One simple rule; density less than water it stays up. density equal it will be suspended (act just like water). density higher, it sinks.
2007-02-26 11:23:52 · answer #2 · answered by Banzan 2 · 0⤊ 0⤋