Stoichiometry!! Please help!! Thanks.?

Question

I have a few stoichiometry problems that I need help with. If you could show your work, then that'd be really, really good! Please put the number of the one you solved next to it. Thanks for anyone who can help me!!

1) N2 + 3H2 ---> 2NH3 What volume of hydrogen is necessary to react with 5 liters of nitrogen to produce ammonia?
2) what volume of ammonia is produced in the reaction in problem one?
3) C3H8 + 5O2 ---> 3CO2 + 4H2O If 20 liters of oxygen are consumed in the above reaction, how many liters of carbon dioxide are produced?
4) 2H2O ---> 2H2 + O2 If 30 mL of hydrogen are produced in the above reaction, how many milliliters of oxygen are produced?
5) 2CO + O2 ---> 2CO2 How many liters of carbon dioxide are produced if 75 liters of carbon monoxide are burned in oxygen? How many liters of oxygen are necessary?

**All these formulas are already balanced. There are more problems below!!

6) N2 + 3H2 ---> 2NH3 What volume of NH3 at STP is produced if 25 grams of N2 is reacted with an excess of H2?
7)2KCLO3 ---> 2KCL + 3O2 If 5 grams of KCLO3 is decomposed, what volume of O2 is produced at STP?
8)How many grams of KCL are produced in probem 7?\
9) Zn + 2HCl ---> ZnCl2 + H2 What volume of hydrogen at STP is produced when 2.5 grams of zinc react with an excess of hydrochloric acid?
10) H2SO4 + 2NaOH ---> H2O + Na2SO4
How many molecules of water are produced if 2 grams of sodium sulfate are produced in the above reaction?
11) 2AlCl3 ---> 2Al + 3Cl2

Again, thanks so much!!! =)

All these problems confused me, because as you can see, they are not very straightforward. There are some weird questions along with them...I hope that someone here on Yahoo can figure it out...

That's okay, J_laviska, I'm too tired to attempt even one of these. Since it is almost 7 right now, I am too lazy to do anything...though, I may have to. How I hate math...

Oh, I do know that 22.4 Liters equals one mole. This is true for any gas. Also, STP stands for standard temperature and pressure, if this helps anyone solve anything...

Basically, there are the number of moles as the number is in front of the element. 2N= 2 moles of nitrogen. Just saying...No one else has answered my question except for j_loviska. Not even fully, I might add. Oh well, at least he tried...

Answer 1

1.) to solve this you need to look at PV=nRT. Because I don't know how many moles of N there are in 5 L of nitrogen gas I can't give you an answer. If you know the moles then you can show that 1 mol of N2 reacts with 3 mol of H2, and then convert mol of H2 to L with PV=nRT.

2.) same as question 1 only instead of 3 mol reacting it's 2.

3.) need amount of moles again.

4.) 15 mL of O2. You know this because you create twice as much H2 as O2.

I'm too tired to look at 5, sorry I couldn't be of much more help than that.

Answer 2

you notice that a million molecule of Fe3O4 corresponds to 3 atomes Fe . so in mass 3*fifty six+4*sixteen = 232g Fe3O4 correspond to 156g of Fe 1g of Fe corresponds to 2.32/a million.fifty six and a million.40 seven g to a million.40 seven*2.32/a million.sixty 8=2.03g Fe3O4 so fraction of Fe3O4 is two.03/40 5 =0.40 5 this provides 4.51%