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A test charge of +9 10-6 C experiences a downward electrostatic force of 15 N when placed at a certain point in space. What are the magnitude and direction of the electric field at this point?
N/C

2007-02-26 10:17:41 · 1 answers · asked by bibun 2 in Science & Mathematics ➔ Physics

1 answers

By definition the electric field equal to the force on the point charge divided by that point charge
E=F/Q
E=15/(9E-6) =1.67 E5 N/C

2007-02-27 03:07:55 · answer #1 · answered by Edward 7 · 0⤊ 0⤋