If the sled starts from rest and has a speed of 8.0 m/s at the bottom, what is the height of the hill?

Question

A child and sled with a combined mass of 45.0 kg slide down a frictionless hill. If the sled starts from rest and has a speed of 8.0 m/s at the bottom, what is the height of the hill?

_____ meters

Understanding the relationship between potential energy, kinetic energy, the conservation of energy and work.

Answer 1

This is classic conservation of energy.

In this case, potential energy at the top of the hill will equal kinetic energy at the bottom of the hill:

m*g*h = 1/2 * m * v^2

The beauty of this is that the mass of the sled is irrelevant to the speed at the bottom of the hill.

So, solving for h:

h = 1/2 * v^2 / g

where g is the gravitational constant 9.8 m/s^2

Answer 2

replace in top is extra or less = preliminary speed x time taken +a million/2 x gravity x time take so, preliminary speed is many times = to very final speed, so replace in top is = 3.8 x time + 9.8/2 x time = 3.8t + 4.9t = 8.7t You do recognize that without time, i will no longer be able to clean up this? and additionally, that weight fairly has no result on speed in projectile action. What you have is a million/2 a parabola, which the equation takes into consideration, in spite of the undeniable fact that it desires a time variable. yet, I incredibly have simplified it to the factor the place i ingredients you your answer in meters in case you provide me a time. i wish this facilitates incredibly.