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So I am having trouble with my basic math and have completely forgotten how to solve equations with scientific notation...

3.00x10^(17) x 6.63x10^(-34)

if you could explain how to get the correct exponent when solving these kinds of equations I would be appreciative...I get the right answer but never the right exponential value...

2007-02-26 06:14:48 · 4 answers · asked by guitar_dah_311 1 in Science & Mathematics Chemistry

4 answers

Follow this carefully, and you will understand:

3.00 x 10^(17) x 6.63 x 10^(-34)

3.00 x 6.63 x 10^(17) x 10^(-34)

19.89 x 10^(17) x 10^(-34)

19.89 x 10^(17 - 34)

19.89 x 10^(-17) Ans

You can move the decimal point, and express the same thing as:

1.989 x 10(1) x 10^(-17)

1.989 x 10^(1 - 17)

1.989 x 10^(-16) Alternative Ans.

2007-02-26 06:23:03 · answer #1 · answered by Scythian1950 7 · 1 0

example:

2^2 * 2^3 = 4 * 8 = 32, which is also (2)^(2+3)

in general
x^n * x^m = x^(n+m)

to answer your question:
3.00x10^(17) x 6.63x10^(-34) is
3.00x6.63x10^(17+-34) = 19.89x10^-17 = .1989x10^19

which would be something like:
0.0000000000000000001989 :):)
(well these last few lines are just for fun :))

hope I helped

2007-02-26 14:32:46 · answer #2 · answered by tomes12 2 · 0 0

when you have so a problem first multiply the exponentials keeping in memory that 10^x *10^y = 10^x+y

here 10^(-34)*10(17) = 10^(-34* +17) =10^-17

after multiply the other numbers 3*6.63 =18.89

so the result is 18.89 *10^(-17)

or 1.889 *10^(-16)

2007-02-26 14:22:29 · answer #3 · answered by maussy 7 · 1 0

Remember in your answer that the correct answer should be

x.yz * 10^ab

you will have only ONE significant figure on the left hand side of the decimal point!

2007-02-26 14:27:09 · answer #4 · answered by Dr Dave P 7 · 1 0

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