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Specific heat of water is 4.18 Joules by degrees celsius

2007-02-26 05:39:14 · 2 answers · asked by cubiche00 1 in Science & Mathematics Earth Sciences & Geology

2 answers

Use the formula :
Energy Needed = Specific Heat Capacity * mass * temperature change

As far as I know the Specific Heat Capacity of water is 4200 J/kg/K

So Energy Needed = 4200 * 100* 20 = 8400000 J or 8.4 MJ

2007-02-26 05:46:25 · answer #1 · answered by slur64 1 · 0 0

100kg*20deg = 2000kcal = 8360kJoules.
QED

2007-02-26 05:45:58 · answer #2 · answered by JJ 7 · 0 0

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