English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

If I need to double the centripetal force on an object moving in a circle, do I need to increase or decrease the object’s speed? And by how much (percent)?

2007-02-26 03:47:02 · 5 answers · asked by GSU 1 in Science & Mathematics Physics

5 answers

The centripetal force is the external force required to make a body follow a circular path at constant speed. The force is directed inward, toward the center of the circle. Hence it is a force requirement, not a particular kind of force. Any force (gravitational, electromagnetic, etc.) can act as a centripetal force. The term centripetal force comes from the Latin words centrum ("center") and petere ("tend towards").

The centripetal force always acts perpendicular to the direction of motion of the body. In the case of an object that moves along a circular arc with a changing speed, the net force on the body may be decomposed into a perpendicular component that changes the direction of motion (the centripetal force), and a parallel, or tangential component, that changes the speed.

2007-02-26 04:30:37 · answer #1 · answered by Anonymous · 0 0

You increase the speed to increase the centripetal force which is proportional to the square of the velocity. So to double, you increase the velocity by the square root of 2, or roughly 0.7. So for a large circular movement, you roughly increase the speed by 70% to double the centripetal force.

2007-02-26 03:56:29 · answer #2 · answered by kyq 2 · 0 0

First i could remark that your formulation isn't valid. F = (m* V * V )/R there is no "g" interior the equation itself. in F = m a, F is the consequent tension. it is mechanically used. there may well be many utilized forces yet whilst an merchandise hurries up then all of us comprehend the consequent of all of them prepare. further in a circle. If it strikes in a circle then F = m a ( as a vector) and F = m v^2 /r wisely shows the consequent tension needed to reason this action. no remember what number guy or woman forces that are utilized all of us comprehend the effective results of all of them prepare. The term for this resultant tension is centripetal tension. it is totally actual. And the term could be used because of the fact it wisely describes the area. whether the terminology isn't continuously used precisely. contained with regards to the plane, the completed of all different forces will equivalent centripetal tension if the airplane is shifting in a circle with consistent velocity. It "balances" in basic terms interior the way that the left hand ingredient of any "equals sign" balances the splendid hand . ingredient. contained with regards to letting the ball pass, you eliminate the strain of the string so which you're actually not any extra forcing the ball to pass in a circle. consequently the ball could flow in a quickly line at consistent velocity. it is the equivalent of combating pushing something. It keeps in a quickly line at consistent velocity in basic terms as your ball does once you end pulling it. ( See Newtons rules). Centrifugal tension is a tension that seems to be latest. it variety of feels as though an merchandise is pulling outwards. that's seen that it is untrue. If an merchandise is incredibly attempting to pass outwards ( a favorable cost being repelled by skill of a nucleus as an occasion) then it hurries up quickly outwards as quickly as the different forces are bumped off. it is not the case for the ball So centrifugal tension isn't splendid besides the fact that there would be situations the place that's a functional fiction..

2016-10-16 12:54:27 · answer #3 · answered by ? 4 · 0 0

A = v^2/r

increase speed by square root of 2

2007-02-26 03:51:35 · answer #4 · answered by Grant d 4 · 1 0

you need to decrease its period, which increases its speed.
Doubling the speed doubles the centripeal force.

2007-02-26 03:50:45 · answer #5 · answered by Matthew P 4 · 0 0

fedest.com, questions and answers