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If a motorcycle is driven around a vertical loop (radius = 12 meters), what is the minimum speed at the top of the loop to ensure the cycle is held to the loop?

2007-02-26 03:46:46 · 1 answers · asked by GSU 1 in Science & Mathematics Physics

1 answers

The centripetal acceleration must equal gravity

Ac = v^2/r = 9.81
v = sqrt(9.81 x 12) = 10.85 m/s = 39.06 km/h

2007-02-26 05:06:13 · answer #1 · answered by catarthur 6 · 0 0

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