Please help me solve this calculus problem!!?

Question

All the real zeros of an equation are –1, 3, and 4. To solve its corresponding inequality, determine the sign in the intervals:

a) x < –1, –1 < x < 4, x > 4
b) x < 3, 3 < x < 4, x > 4
c) x < –1, –1 < x < 3, 3 < x < 4, x > 4
d) y < –1, –1 < y < 4, 3 < y < 4, y > 4

Answer 1

To find the solution check the signs of (x + 1) , ( x -3) and (x - 4) in each interval, and multiply them.
If the number of negative factors is odd the product is negative, otherwise it is positive.