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Use zeros and end behaviors to solve: -(x + 6)(x + 3)^2 < 0

2007-02-26 02:33:26 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

(x + 3)^2 is always positive, so you can feel free to divide both sides of the equations by it without changing the sign '>'

-(x + 6) < 0

-x -6 < 0

-x < 6

x > -6

2007-02-26 02:41:15 · answer #1 · answered by Amit Y 5 · 0 0

x>-6

2007-02-26 02:37:48 · answer #2 · answered by lastdemocratalive 2 · 0 0

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