Use zeros and end behaviors to solve: -(x + 3)(x + 1)(x - 1)(x - 2) LESS THAN OR EQUAL TO 0
2007-02-26 02:24:19 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Your zeros are given by the factors: x=-3, x=-1, x=1, x=2.
Plug a value for x in between and see what happens!
2007-02-26 02:37:26 · answer #1 · answered by Anonymous · 0⤊ 0⤋
-(x+3) (x+1)(x-1)(x-2)<0
multiply by -1
(x+3) (x+1) (x-1)(x-2)>0 the roots are -3 , -1, +1 , +2
xwe make a table and look at the sign
-infinite -3 -1 +1 +2 +infinite
x+3 - + + + +
x+1 - - + + +
x-1 - - - + +
x-2 - - - - +
Product + - + - +
so the condition is fulfilled for the following intervals
x infinite to -3 included
-1 to +1 with limits included
and xhigher or equal to +2
and
2007-02-26 10:44:53 · answer #2 · answered by maussy 7 · 0⤊ 0⤋