Factor 4x^3 + 4x^2 – x - 1
2007-02-26 01:33:01 · 4 answers · asked by slow_math 1 in Science & Mathematics ➔ Mathematics
It helps to look at it as (4x^3 + 4x^2) - (x + 1). Then you can pull out a factor of 4x^2 from the first grouping to get 4x^2(x + 1) - (x + 1) From that, you can see that you have (4x^2 - 1)(x + 1). Then 4x^2 - 1 is pretty easy to break down as (2x + 1)(2x - 1) since a^2 - b^2 = (a + b)(a - b). So the final answer is (2x + 1)(2x - 1)(x + 1)
2007-02-26 01:39:28 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
4x^3 + 4x^2 - x - 1 = 0
(4x^3 + 4x^2) - (x + 1) = 0
4x^2 ( x+1 ) - ( x-1) = 0
2007-02-26 09:55:10 · answer #2 · answered by silisulu 1 · 0⤊ 0⤋
we know that
4x^3 + 4x^2 – x - 1=
4x^2(x+1)-(x+1)=
(4x^2-1)(x+1)=
(2x+1)(2x-1)(x+1)
2007-02-26 09:43:56 · answer #3 · answered by hyonyoungm 3 · 0⤊ 0⤋
(2x-1)(2x^2+3x+1) =
(2x-1)(x+1)(2x+1)
2007-02-26 09:43:01 · answer #4 · answered by mulla sadra 3 · 0⤊ 0⤋