An aquarium has a recangular base that measures 100 cm by 40 cm and has a height of 50 cm. The aqaurium is filled with water to a depth of 37 cm. A rock with a volume of 1000cm^3 is then placed in the aquarium and completely submerged. By how many centimeters does the water level rise?
Choices...
A) 0.25
B) 0.5
C) 1
D) 1.25
E) 2.5
2007-02-25 23:56:22 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
A) 0.25
The aquarium's current water level is 100 x 40 x 37 cm = 148,000 cm^3.
a 1000 cm^3 stone is submerged. So the water should displace this 1000 cm^3. The area of the base is 100 x 40 = 4000 cm^2.
Thus volume / area of base = water level risen.
1000 / 4000 = 1/4 = 0.25.
2007-02-26 00:00:58 · answer #1 · answered by Tiger Tracks 6 · 1⤊ 0⤋
The answer should be 0.25cm. If you divide 1000cm3 by 4000cm2 you'll get .25cm.
Another Way to look at: The original volume of water is 100*40*37(water)=14800. The volume of water plus rocks is 14800+1000=15800. The difference is 1000cm3. The area of the base of the tank is 4000cm2. Divide 1000cm3 by 4000cm2 and you get .25cm.
2007-02-26 08:20:44 · answer #2 · answered by Lost in PA 2 · 0⤊ 0⤋
volume of the rock=1000 cm^3
volume of water displaced=volume of the rock
=1000cm^3
suppose the water rises by x cm,
volume of water displaced=x cm*base area of the aquarium
=x*100cm*40cm
=volume of the rock
=1000cm^3
=>1000cm^3=x*4000 cm^3
=>x=.25cm
got it????
2007-02-26 08:31:08 · answer #3 · answered by poornima l 1 · 0⤊ 0⤋
The answer is A. Raj was nice enough to type the entire process, so I won't repeat, but the answer is correct. it's 0.25.
2007-02-26 08:10:43 · answer #4 · answered by TJTB 7 · 0⤊ 0⤋
1000/4000=0.25cm
2007-02-26 08:00:38 · answer #5 · answered by lastdemocratalive 2 · 0⤊ 0⤋
a. .25
2007-02-26 09:05:36 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Time to go back to school!!!!
2007-02-26 16:15:56 · answer #7 · answered by diamondbullet66 4 · 0⤊ 0⤋
answer is A)0.25
2007-02-26 08:04:39 · answer #8 · answered by Anonymous · 0⤊ 0⤋