Find this x and y then can do the 2nd question. 3(x)-2(y) = 4
If... x is 2, y is 2
then... the ans is 3(2)-2(2) = 2 (The Wrong answer coz it tell u to find 4)
If... x is 2, y is 1
then... the ans is 3(2)-2(1) = 4 (Correct Ans)
THEN,...
DO 2nd Question!!!
1st question said that x is 2, y is 1 then let me double check on 2nd question!
3(x)+6(y)=12
3(2)+6(1)=12 (It is the correct!!)
That means that x is 2 , y is 1. :D
*P.S.* : HOPE U UNDERSTAND!
2007-02-26 00:23:23
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answer #1
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answered by PolytechnicStudent :] 3
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or you can rearrange you equation
>>> 3x = 4 + 2y(equation 1 )
>>> 3x = 12-6y ( equation 2)
so equa1 = equa2
4+ 2y = 12 - 6y
6y + 2y = 12 - 4
8 y = 8
y = 8/8
y = 1
To find x, substitute 1 into any of the equations,could be
3x = 4 + 2 (1)
3x = 6
x = 6/3
x = 2
So, y = 1 and x = 2
2007-02-26 03:32:48
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answer #2
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answered by pieces of me 1
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the first thing to do is to multiply 3x-2y=4 by -1 which will give you
-3x+2y= -4 by elimination:
(-3x+2y= -4) + (3x+6y=12) ... this will give you the answer
of y=1
To get x just substitute the value of y to one of the equations:
3x+6y=12
3x+6(1)=12
3x= 6
x=2
2007-02-25 23:55:55
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answer #3
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answered by anything 2
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3x+6y=12
3x-2y=4
Multiply the II eqn with a - and add them both
3x+6y=12
-3x+2y=-4
8y=8 -> y=1
Substitute Y in any of the equations
3x-2=4 -> 3x = 6 => x = 2
2007-02-25 23:51:45
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answer #4
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answered by sdbskrl 2
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Multiplying the first relation by -1 you have
-3x+2y=-4
Then add the above relation with the second one you have been given. This way u got
8y=20
Which leads to y=5/2
If u put the y value u have found above into one of the two relation u got u will find out that x=3
So x=3 and y=5/2
Hope I helped
2007-02-25 23:56:18
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answer #5
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answered by Anonymous
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3x + 2y = 4 ----------------(A) 6x + 4y = ?2 --------------(B) the following, a1 ---b1 ----c1 ---- = ----- ? ---- a2 ---b2 --- c2 those are the respective coefficients in equations A and B i.e. 3 --- --2 ---- 4 ---- = ----- ? ---- 6 ------4 --- - 2 a million --- --a million ----- 2 ---- = ----- ? ---- 2 ------2 --- - a million in this subject, the equipment of linear equation has no answer as they're parallel lines
2016-12-04 23:25:51
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answer #6
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answered by ? 4
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