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Thanks guys

2007-02-25 23:35:48 · 3 answers · asked by steveo 1 in Science & Mathematics Mathematics

3 answers

5 /√3 - 1=

5 / √2 =

5√2 / √2 √2 =

5√2 / √4 =

5 √2 / 2

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2007-02-26 00:07:54 · answer #1 · answered by SAMUEL D 7 · 0 0

Since (a + b)(a - b) = a^2 - b^2, you can "move" a sum or difference of square roots (or a square root and a rational) from the denominator to the numerator (or vice versa) by multiplying both top and bottom by the a +/- b term with sign opposite to the one you are trying to rationalize.

So for 5 over (sqrt(3) - 1), you move the square root in the difference from bottom to top by mutiplying both bottom and top by the corresponding sum:

= (5 times (sqrt(3) + 1)) over ((sqrt(3) - 1) times (sqrt(3) + 1))

The denominator simplifies to
( sqrt(3) )^2 - 1^2 = 3 - 1 = 2.

Dan

2007-02-26 07:44:29 · answer #2 · answered by ymail493 5 · 0 0

(5sqrt(2))/2

2007-02-26 07:40:26 · answer #3 · answered by Anonymous · 0 0

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