given f(g(x))=7x^2+56x+20 and f(x)=7x^2-92, what is f(x)?
2007-02-25 23:24:37 · 7 answers · asked by pk132 1 in Science & Mathematics ➔ Mathematics
sorry, the question's supposed to be what is g(x).
2007-02-25 23:44:45 · update #1
f(x)=7x^2-92
2007-02-25 23:28:12 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You already have the answer.
f(x) = 7x^2-92
2007-02-25 23:32:53 · answer #2 · answered by AJ 3 · 0⤊ 0⤋
I take it that you mean what is g(x).
fg(x)=7x²+56x+20 ->eqn 1
f(x)=7x²-92
So fg(x) = f[g(x)]
= 7[g(x)]²-92 ->eqn 2
Thus,
eqn 1 = eqn 2
7x²+56x+20 = 7[g(x)]²-92
7[g(x)]² = 7x²+56x+20+92
7[g(x)]² = 7x²+56x+112
[g(x)]² = x²+8x+16
Factorise x²+8x+16
[g(x)]² = (x+4)²
Therefore,
g(x) = x +4
2007-02-25 23:41:30 · answer #3 · answered by tabletennisrulez 2 · 0⤊ 0⤋
f(x)=7x^2-92
2007-03-05 19:55:08 · answer #4 · answered by Anime Lover 3 · 0⤊ 0⤋
if u mean what is g(x) then the answer would be
f(g(x))=7g(x)^2-92=7x^2+56x+20
7g(x)^2=7x^2+56x+112
g(x)^2= x^2+8x+16=(x+4)^2
g(x)=ABSOLUTE(x+4)
2007-02-25 23:32:35 · answer #5 · answered by A New Life 3 · 0⤊ 0⤋
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2016-11-25 23:56:02 · answer #6 · answered by nadem 4 · 0⤊ 0⤋
7x^2-92
Next!
2007-02-25 23:35:01 · answer #7 · answered by gebobs 6 · 0⤊ 0⤋