Help, anyone?

Question

partscoretotal1--0.1The distinctive odor of vinegar is due to acetic acid, HC2H3O2. Acetic acid reacts with sodium hydroxide in the following fashion: HC2H3O2(aq) + NaOH(aq) H2O(l) + NaC2H3O2(aq). If 2.55 mL of vinegar requires 34.9 mL of 0.1036 M NaOH to reach the equivalence point in a titration, how many grams of acetic acid are in a 1.00 qt sample of this vinegar? (1 L = 1.0567 qt)

____________ g/qt

Answer 1

A 0.1036M solution contains 0.1036 mole NaOH in one liter of solution. 34.9mL of that solution contains 0.0349*0.1036 mole NaOH, which is the amount that reacted with the acetic acid.

The molecular mass of acetic acid is 60.05 g/mole (I got it from http://en.wikipedia.org/wiki/Acetic_acid or you can add it up from the atomic components).

Since the equation shows one molecule of acetic acid reacting with one molecule of NaOH, then the no of moles of acetic acid in the solution = no moles of NaOH = 0.0349*0.1036 moles. The mass of the acetic acid is then 0.0349*0.1036*60.05g, and that was contained in 2.55mL. 1000/1.0567 = 946.342 mL in a quart. The no of grams in a quart is then 946.342/2.55 * no grams in 2.55mL, which is calculated above.

I got 80.58g/qt. but I need to check my arithmetic.