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How do you factor something with four or more terms? or is there a quicker way to find the zeroes? i looked in my book, but i didn't really understand. Example problem: 6x^3-29x^2-45x+18=0

2007-02-25 17:26:24 · 1 answers · asked by good advice 3 in Education & Reference Homework Help

1 answers

yes - look at all of your values that have x's and see how many x's you can factor out.

for example, 6x^3, -29x^2, and -45x all have at least ONE x in them, so you can bring that x to the outside, and make the equation:

x(6x^2-29x-45) + 18 = 0

now work the problem like you would with a regular x^2 polynomial, but don't forget about your first x and your +18 at the end.

2007-02-25 17:32:14 · answer #1 · answered by mighty_power7 7 · 0 0

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