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4 answers

This is not so much a direct amswer as a few calculations which might be helpful.

S.Sweet + ?O2 --> xCO2 + yH2O

24.45 g / 44.01 g/mol = 0.5556 moles CO2

all of the Carbon came from the S.Sweet
12.01 g/mol * 0.5556 moles = 6.673 grams Carbon

10 g / 18.02 g/mol = 0.5549 moles H2O

all of the Hydrogen came from the S.Sweet
1.008 g/mol * 0.5549 moles * 2 = 1.119 grams Hydrogen

6.673 g + 1.119 g = 7.792 g C+H
10 - 7.792 = 2.208 grams O

2.208 g / 16.00 g/mol = 0.138 moles O

from mole ratios:
C4H8O

2 C4H8O + 11 O2 --> 8 CO2 + 8 H2O

2007-02-25 15:38:23 · answer #1 · answered by Richard 7 · 10 0

no idea...can u give me ur email adress.i wil ask my brother..if he knows..he is doin chemical and biochemical engennering...(mashallah..god nazarebas se bachayay)....

ps...dont worry about ^^^^^^^^^ its nothing....

2007-02-25 16:49:19 · answer #2 · answered by adventureisrighthere 2 · 1 0

you probably knew the answer so why ask.

2007-02-25 19:14:30 · answer #3 · answered by Anonymous · 1 0

It's easy:

C4H8O

2007-02-26 06:43:41 · answer #4 · answered by Sol Poente 5 · 1 0

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