what quantity of heat energy is released when 265 g of liquid water freezes?

Answer 1

When water change to ice,
Heat of Fusion = 334 kJ/ kg
For 265 g of water

Heat Released
= 334 kJ/kg x 0.265 kg
= 88.51 kJ

Answer 2

each and every time a substance undergoes somewhat substitute then the potential (accordingly) released = mass of substance * warmth of transformation warmth of transformation = warmth of fusion of H2O = 333.fifty 5 J/g potential released = 333.fifty 5 J/g * 138 grams Then divide by one thousand to get kJ. The equation utilized by the above answerer is in basic terms used whilst there's a temperature substitute (no longer observed by section substitute) I disagree with the above answerer. I promise then you whilst there's somewhat substitute from liquid to good warmth would be released. warmth of fusion it potential whilst there's a fusion there's a warmth (enthalpy substitute)