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a force of 531 at -40 degrees newtons is required to give a 160 kg mass an acceleration of 1.31 m/s^2 . what is the force produced by the kinetic friction? what is the coefficient of kinetic friction?

2007-02-25 14:27:22 · 2 answers · asked by judykharrison 1 in Science & Mathematics Physics

2 answers

Let us say that the angle is with respect to the normal of the mass, than the force applied is 531cos(40 Degrees).

(160*1.31) = 531*cos(40 Degrees) - 160*mu_k*displacement

2007-02-25 14:37:52 · answer #1 · answered by Anonymous · 0 0

It's necessary to know whether the 160 kg mass is accelerating horizontally or perhaps down a -40 degree slope (a standard position angle measured CLOCKWISE, because of the negative, with respect to a positive horizonal x axis)

2007-02-25 23:39:44 · answer #2 · answered by answerING 6 · 0 0

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