a block that has a mass of 24 kg is initially at rest on an inclined plane of 25 degrees. (a) find the component of the weight that is parellel to the plane. (b) find the componentof the weight that is perpendicular to the plane. (c) find the maximum find the maximum force of static friction if the coefficient of static friction is .65. will the block slide down the plane?
2007-02-25 14:11:22 · 2 answers · asked by mandy 1 in Science & Mathematics ➔ Physics
When an object is on a plane that makes an angle theta with respect to horizontal, the component of the weight that is parallel to the plane is always mgsin(theta). The component of the weight that is normal or perpendicular to the plane is always mgcos(theta). Those will give you the answers to (a) and (b). The maximum friction force for this scenario is equal to the parallel component of the weight. (Newton's second law says the sum of the forces forward equal the sum of the forces backward, if the acceleration is zero. So the force of friction equals the parallel component of the weights.)
If the coefficient of static friction is 0.65, the the force required to start the mass sliding is 0.65 mgcos(theta). If this force is greater than mgsin(theta) then the mass will NOT slide. If it is greater than mgsin(theta) then it will slide.
2007-02-25 14:20:00 · answer #1 · answered by Dennis H 4 · 0⤊ 0⤋
It looks like you are doing the same "ramp with friction" homework as someone else on here ... look around and you might find the answer. To get the parallel and perpendicular vectors, use Pythagorean Principle. It's been a long time but I suspect one will be the sine function and the other will be the cosine function of 25 deg.
2007-02-25 22:23:06 · answer #2 · answered by Anonymous · 0⤊ 0⤋