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can you help with physics: calculate ideal efficency of a heat engine that has a temperature of 5400k.?

where the fuel is burned and a sink temerature of 720k.

2007-02-25 13:31:53 · 1 answers · asked by Eric 1 in Science & Mathematics ➔ Physics

1 answers

η=(T1-T2)/T1=(5400-720)/5400=86.7%

2007-02-25 14:52:41 · answer #1 · answered by Rob M 4 · 0⤊ 0⤋

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