How do i write the equation of a parabola in standard form given: Focus (0,-4) vertex (0,0)?

Answer 1

Use (x - h)^2 = 4p(y - k) and plug in what you know. (h, k) is the vertex (0, 0) and p is the distance from your vertex to the focus (-4). So:

(x - h)^2 = 4p(y - k)
(x - 0)^2 = 4(-4)(y - 0)
x^2 = -16y
y = x^2/16

Answer 2

a million) this would be a parabola this is symmetric to the x-axis and opens to the left. the prevalent sort is y^2 = 2px the place p is the directed distance from the directrix to the concentration. 2) it is likewise a parabola this is symmetric to the x axis. Vertex is at (3,2). 3) x^2 -12x +36 -8y -36 + 20 = 0 (x-6)^2 - 8(y+sixteen) = 0 (x-6)^2 = 8(y+sixteen) <-- prevalent sort Vertex at(6,-sixteen)