You testify as an "expert witness" in a case involving an accident in which car A slid into the rear of car B, which was stopped at a red light along a road headed down a hill (Fig. 6-27). You find that the slope of the hill is = 12.0°, that the cars were separated by distance d = 26.0 m when the driver of car A put the car into a slide (it lacked any automatic anti-brake-lock system), and that the speed of car A at the onset of braking was v0 = 17.5 m/s.
im getting all kinds of answers w/ v^2= vo^2 + 2a(x), all wrong
2007-02-25 11:52:48 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
sorry, i have to find final velocity at impact when coefficent of friction is at .6
then again at .1
2007-02-25 13:32:57 · update #1
What's the question?
2007-02-25 12:26:36 · answer #1 · answered by sojsail 7 · 0⤊ 0⤋
The rigidity which reasons the block to enhance up is the element of the blocks weight that's parallel to the ramp. rigidity parallel = m * g * sin ? Acceleration = g * sin ? = 9.8 * sin 60? when you consider that we don't be responsive to the time, use right here equation to make certain the suited speed. vf^2 = vi^2 + 2 * a * d, vi = 0 m/s, d = 7 m vf^2 = 2 * 9.8 * sin 60? * 7 vf = ?(137.2 * sin 60) the suited speed is approximately 10.9 m/s.
2016-10-01 23:53:33 · answer #2 · answered by czech 4 · 0⤊ 0⤋
I am totally at sea as to what the question is.....
2007-02-25 12:24:28 · answer #3 · answered by Steve 7 · 0⤊ 0⤋