How large or small would an asteroid have to be, for you to be able to jump off it and escape?

Answer 1

It would depend on the density of the asteroid, which effects its surface gravity, and how fast you can jump. If you know the radius of the asteroid (r), and its surface gravity (a), you can calculate its escape velocity with (2·a·r)^.5.

Answer 2

Assuming a uniform distribution of mass and spherical shape, the asteroid would have to obey the equation:
2.364E-5*r*√ρ = Ve

You have to decide what the Ve is; that will give you the relationship between r & ρ. For ρ = 1000 kg/m³, and a jump velocity of 1 m/s, this gives a radius of about 1339 m.

Answer 3

Suppose your velocity of jumping is u and the height to which you jump on earth is h then
u=square root of 2gh
Since u should be equal to escape velocity from asteroid,
u=square root of 2g(asteroid) R where R is radius of asteroid.
As g depends on density and radius, assuming density to be same as density of earth we get,
radius of asteroid =square root of h x radius of earth

Answer 4

Hi. It's escape velocity would have to be less than the velocity the jumper could achieve. A really REALLY strong jumper could, I suppose, jump off the Earth.

Answer 5

I'm not really into physics, but I don't think anyone would be able to do anything like that and survive because of the speed that it would be travelling.

Answer 6

mythbusters did something similar to this but with a falling elevator.

There's only a billion to one chance you can escape.