A banked circular highway curve is designed for traffic moving at 60 km/h. The radius of the curve is 230 m. Traffic is moving along the highway at 35 km/h on a rainy day. What is the minimum coefficient of friction between tires and road that will allow cars to negotiate the turn without sliding off the road?
2007-02-25 11:11:41 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The component of weight that is parallel to the pavement, towards the inside of the curve, is m*g*sinΘ. 60 km/hr is the magic speed, so the centripetal force must equal m*g*sinΘ.
m*g*sinΘ = m*v^2/r
where v is 60 km/hr converted to m/s and r is 230 m. Find Θ.
Then at 35 km/hr, m*g*sinΘ is larger than m*v^2/r. The friction, μ*m*g*cosΘ, needs to make up the difference.
2007-02-25 13:03:48 · answer #1 · answered by sojsail 7 · 0⤊ 0⤋
What is the weight of the car, and what model? Tire size is also helpful and maybe a tread description.
2007-02-25 19:17:21 · answer #2 · answered by slacker3153 1 · 0⤊ 1⤋