ok this is a combustion problem., i know u add O2 when something burns ^^ anybody care to explain how to balance equations?!
2007-02-25 09:36:20 · 3 answers · asked by kitty~princess 1 in Science & Mathematics ➔ Chemistry
Titanium burns when heated in oxygen to 610 °C (1,130 °F) or higher, forming titanium dioxide:
Ti (s) + O2 (g) --> TiO2 (s)
Titanium can also "burn" in pure Nitrogen gas (it burns at 800 °C or 1,472 °F) to give the nitride:
2 Ti (s) + N2 (g) --> 2 TiN (s)
When ignited in air (a mixture containing both nitrogen and oxygen gases), Titanium metal will produce both the oxide and the nitride.
AUTO-IGNITION TEMPERATURE (F): 2200 °F for metal in air, 480 °F for powder in air.
EXTINGUISHING MEDIA: Dry table salt or Type D fire extinguisher.
SPECIAL FIRE-FIGHTING INSTRUCTIONS: Remove uninvolved material; allow fire to burn out. Fire can be controlled by covering with dry salt or powder from Type D fire extinguisher. Carbon dioxide is not effective.
UNUSUAL FIRE AND EXPLOSION HAZARDS: Dry titanium burns slowly while releasing much heat. Water applied to burning titanium may cause an explosion. Piled chips may burn vigorously.
2007-03-01 08:45:29 · answer #1 · answered by Richard 7 · 12⤊ 0⤋
Titanium burns really well. Since it has a valency of 4, its oxide has the formula TiO2.
So Ti + O2 ----> TiO2.
2007-02-25 17:53:48 · answer #2 · answered by Gervald F 7 · 0⤊ 1⤋
its not really an "explaining" thing....more like trial and error...i kno u dont wanna hear that but thats how it is...i always hated that crap...in case ur asking for the overall balancing...ur tryina get the number of one element on one side of the arrow wit the other...how i do it is i make a list of all the elements on one side and the same list on the other side of the arrow....count how many mols are on either side...and "trial and error"....hope this helps...i despise that part of chemistry....till i got to Re-dox reactions...
2007-02-25 17:46:50 · answer #3 · answered by unpredictedmystery 3 · 0⤊ 1⤋