Eeeeks! Math Question~?

Question

What is the least value of y that satisfies this equality?

|4+x| + |5+y| ≤100

um... theres no other information given. nuttin bout x. which is exactly why i turned to yahoo answers. sryy~

Answer 1

|4+x| could be zero, but never less, so x would be -4 when y is a minimum.
Then |5+y| ≤ 100
5+y ≤ 100; y ≤ 95 is one answer
-(5+y) ≤ 100; -5 -y ≤ 100; -y ≤105; -105 ≤y is the other answer,
So y = -105 is the least value of y that satisfies the equality.

Answer 2

a million. It provides all the guidance you like. Sale cost is comparable to checklist cost (L) minus decrease cost (D). Sale cost equals L - D Sale cost = L - D For a notice project you could basically make up a catalogue cost (how a lot an merchandise sells for) and a chit (how a lot off of the cost you provide ($20.00 as an occasion). 2. in view that x is your "considerable" variable, first isolate it. ax = b => x = b/a then basically make up 2 numbers the place b/a = 3 b = 9 and a = 3 artwork nicely. if so it could be 3x = 9. x/b = a => x = a*b so then discover 2 numbers that multiply mutually to get 3 including a = a million and b = 3. x/3 = a million 3. first get them right into a variety without entire variety. Multiply each denominator by utilising the entire variety and upload that to the numerator. 5 2/7 = ((7*5) + 2)/7 = (35 + 2)/7 = 37/7 2 3/8 = ((2*8) + 3)/8 = (sixteen + 3)/8 = 19/8 then discover the backside straight forward denominator. subsequently fifty six so multiply each by utilising fifty six/fifty six (i.e. a million) fifty six/fifty six * 37/7 then you definately can use the cancel out approach (that's what I call it besides) (fifty six*37)/(7*fifty six) = (8 * 37) / (a million * fifty six) = 296/fifty six same for the different one 19/8 * fifty six/fifty six (fifty six * 19)/(8 * fifty six) = (7 * 19) / (a million * fifty six) = 133/fifty six deliver them mutually now 296/fifty six - 133/fifty six = (296 - 133)/fifty six = 163/fifty six = 2 fifty one/fifty six 4. back for this one you additionally could make up something. such as you have 3 animal pens in a farm and a entire of 21 animals what number animals are you able to put in each pen to ascertain they're frivolously disbursed?

Answer 3

For an unknown x, y=-105.
Assume the value for x resuts in a minimum for |4+x|. X would be -4, causing |4+x| to be 0 (minimum for any absolute value equation).
Therefore, 0+|5+y| ≤100, or |5+y| ≤100.
Solve and you get y≤95 or y≥-105.
The question asks for the minimum value, hence y=-105.
Hope I've helped! =)

Answer 4

x<96 x has to be less than 96
y<95 y has to be less than 95

lets say x=10 which falls in the range above and y=20 which also falls in the range above

|4+x| + |5+y| ≤ 100 equation
|4+10| + |5+20| ≤ 100 substitute
|14| + |25| ≤ 100 addition
14 + 25 ≤ 100 absolute value
39 ≤100 solution

hope this helps

Answer 5

The smallest value [4+x] can be is 0, thus x cannot be less than -4.
[4+(-4)] + [5+y] lesser or egual to 100.

so the answer has to be -105.

Answer 6

Well I believ then that y could equal anything below 96 (or less than or equal to 95). Since I do not know what x is I cant tell you excactly what it is. check in your math book and see if they give x

just put - and then an eight on it's side (negative infinity)

Answer 7

x and y are changeable numbers they could be anything.

That is why it is an inequality.

Now the true answer is negative infinity for both y and x.

But you might be somewhere else and you don't figure that out until later.

Answer 8

Well, this question is pretty much impossible, because the lower you make Y, the higher you can make X.

Answer 9

not enought information. i dont know what X is. but it is probably

Y=1

Answer 10

i'm not sure but i think its 9...haven't taken algebra in a long time