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A solid disk rotating at 33rpm is slowed by friction, stopping after 10 seconds. Find the angular aceleration in rad/s²

2007-02-25 08:57:02 · 1 answers · asked by dqmiddleman 2 in Science & Mathematics Physics

1 answers

By definition
a=w/t
a- angular acceleration (usually alpha) in rad / sec^2
w - angular velocity in rad /sec
t - time
w=2pi (rpm)/(60 sec)
a=2pi (rpm)/[(60 sec)(t)]
a=2 x (3.14159..) x 33/(60 x 10)
a=0.345 rad/sec
I hope it helps

2007-02-25 09:19:23 · answer #1 · answered by Edward 7 · 0 0

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