physics help please?

Question

Motion in 2-D question?
A small pane takes off at a constant velocity of 150 km/hour at an angle of 37 degrees. At 3.00 s a)how high is the plane above ground and b) what horizontal distance has the plane traveled from the liftoff point?

Answer 1

Hi!

You need to draw a little diagram of a right-angled triangle

You know the angle is 37 degrees.

The hypotenuse is how far the plane has actually flew.

The adjacent side is the horizontal distance it has traveled.

The opposite side is the vertical height of the plane.

The plane is travelling at 150 Km/h, which is
= 150,000 / (60 x 60)
= 150,000 / 3600
= 41.67 m/s
BUT it flies for 3s, so:
41.67 x 3 = 125m the plane has flown in 3s

So the hypotenuse is 125m

You can use normal trigonometry now to solve the triangle.

Answer 2

first convert to m/s by multiplying by 10/36
150(10/36)=125/3m/s find how far it goes in 3 seconds...=125m
a)do sin37(125)
=75.23m
b)do cos37(125)
=99.83m