There are some marbles in a bag. They are either blue or green. The probability that a blue marble is chosen 1/8.
a) what is the probability of choosing a green marble?
b) One marble is taken out of the bag. It is blue.
What is the smallest number of green marbles there could be in the bag?
c) Another marble is taken out of the bag. It is also blue.
Using this information, what is the smallest number of green marbles there could be in the bag ?
2007-02-25 07:22:48 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
a) 7/8, .875, or 87.5%
b) Seven
c) Fourteen
2007-02-25 07:33:34 · answer #1 · answered by Jake S 2 · 0⤊ 0⤋
Well, if the odds are 1 in 8, then there are 8 marbles total, leaving 7 out of 8 as the odds for the 1st marble being green instead of blue. Odds are simply the ratio of one color to the other. With 1 blue marble removed, the fewest green marbles in the bag would be 7. If another blue marble is removed, then the minimum number must be 14 green marbles remaining to have the odds 1/8 (which is 2/16) when reduced to lowest terms).
2007-02-25 15:46:01 · answer #2 · answered by rowlfe 7 · 0⤊ 0⤋
a) 7/8=14/16
That's the only one I know for sure. Good luck!
2007-02-25 15:28:18 · answer #3 · answered by Dee 6 · 0⤊ 0⤋
a) 7/8
b) 7
c) 14
2007-02-25 16:45:52 · answer #4 · answered by Anonymous · 0⤊ 0⤋
a) 7/8
b) 7
c) 14
2007-02-25 15:27:59 · answer #5 · answered by kirsty rocks 2 · 0⤊ 0⤋