Physics question?

Question

the earth revolves about its axis every 24 hours.find the magnitude
of the average acceleration of a point on the equator over 6-hour time interval.(the radius of the earth is 6.38*10^6M)

can someone explain it to me?

Answer 1

first find the circumference of the earth.
2pi(6.38x10^6)=4.009x10^7
to find velocity, do circumference over time, so (4.009x10^7)/(8.64x10^4)=463.97
a=v^2/r
a=.0337m/s^2
acceleration stays constant always...