This is a very standard kind of stoichiometry question. First, convert the mass of N2 into moles by dividing by its molar mass (28.0 g/mol). Then, use the coefficients of the balanced chemical equation to convert moles of N2 into moles of H2 (multiply the moles of N2 by 3). Finally, multiply the moles of H2 by the molar mass of H2 (2.00 g/mol) to get grams of H2.
You can then repeat the calculation, except you'll convert the moles of N2 into moles of NH3 by multiplying by 2, and then multiply that by the molar mass of NH3 to get grams of NH3.
2007-02-25 07:02:11
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answer #1
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answered by hcbiochem 7
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The question is posed in grams, but we have atoms or molecules reacting. So, we must convert from grams to molecules. The "molar mass" of a substance tells us how many molecules there are in a gram. This is expressed as "mol" So, steps would be:
1. Find molar mass of nitrogen from a table in a textbook.
2. Find the number of molecules in 50 grams of N from 1.
3. Find number of molecules that will react with this from the equation given.
4. Convert this back to gram by again looking at the mol values in your textbook.
5. Shortcut to the second answer: 50grams + your first answer.
Or, if they want steps ;) calculate the number of mol you had according to the equation and the amounts you calculated already, then convert it back to grams..
2007-02-25 07:07:45
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answer #2
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answered by DJ 1
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Use the factor-lable method to do these kinds of problems.
Given x factor = Answer
Your given is 50 g N2
You have to convert this to moles of N2 first.
(ALWAYS when given grams convert to moles).
Multiply 50g N2 x 1 mol N2/mass of 2 atoms of nitrogen (get this from your periodic table). Cancel grams and now you are in moles of N2.
Now you multiply this by the molar ratios of what you want to what you are given. You get this from your balanced equation: 3 mol H/1 mol N2.
Cancel your units. Now you should be in mols of H.
Your question asked for grams. So now you need to multiply your answer by a factor that relates grams to moles of hydrogen.
2.0 g H2/1 mole H2.
Cancel your units and all you should have left are grams of H2.
This is your answer. Put it in 1 significant digit as this is how many significant digits your given has.
HOPE THIS HELPS.
CHEMISTRY TEACHER
2007-02-25 07:07:16
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answer #3
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answered by CAROL P 4
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Molar mass of N2 is 28.0 g/mol; 50.0 g of N2 is a million.786 mol; each and each mole of N2 reacts with 3 moles of H2, so 3*a million.786 moles of H2 will react; the molar mass of H2 is two.00 g/mol, so which you have 2*3*a million.786 g of H2 or 10.7 g H2 are needed to react thoroughly.
2016-10-16 11:30:38
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answer #4
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answered by ? 4
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50.0 g N2 ;1 mol N2 ; 3 mol H2 ;2g H2
------------ x ; ---------- x ; ----------- x ;---------- ;=;10.7 g H2
1 ;28g N2 ;1 mol N2 ;1 mol H2
(Note: ( ; ) seperates numbers, sighn's, conversions)
OR
50.0/ 28.02 x 3 x 2= 10.71428...... ---> 10.7 (Significant Fig.)
2007-02-27 18:18:55
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answer #5
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answered by Auxi 2
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