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f(x)= -3x^(x+2)

i keep getting the same wrong awnser each times, you help is appreciated thanks

2007-02-25 06:44:47 · 3 answers · asked by mathguru45 1 in Science & Mathematics Mathematics

3 answers

the domain is all the real numbers

the range is all the real numbers less than 0

2007-02-25 06:52:55 · answer #1 · answered by SS4 7 · 0 0

Domain.

well the -3 part has no affect on the domain, so look at x^(x+2)
all positive values for x are fine, as is 0... so [0,+inf) is ok
the problem comes in when:

x is negative
and x+2 is a fraction with a even denominator and an odd numerator). Let looks at all the cases

negative^(even/even) <- defined
negative^(even/odd) <- defined
negative^(odd/even) <- not defined
negative^(odd/odd) <- defined

if x is even/odd x+2 will be the same.
if x is even/even x+2 will be as well, and the same for the other cases

How to write that as a domain? can't tell you

x!= q/p where q is odd and p is even and q*p = -1 U [0,+inf)

range, not sure, as x gets large x^(x+2) goes to infinity, but times -3, -infinity is the left end. 0 is not included since there isn't anything that you can raise to a power and get 0

sorry couldn't be of much help

2007-02-25 07:10:22 · answer #2 · answered by radne0 5 · 0 0

The domain: x>0
The range : all negative numbers (zero Is NOT included)

2007-02-25 06:57:02 · answer #3 · answered by santmann2002 7 · 0 0

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