math help please?

Question

i just cant seem to get this , mybe because i am just tired today

but i am doing inequalities

and i have an inequality like this : s < -3s

now what are the possible numbers that s can be

i know its -2 , - 1 , 0 , 1 , 2 , 3 and all but than there is an s by the -3 which i think means times -3 by s itself

thankss

Answer 1

s < -3s. Now add 3s from both sides to obtain
s + 3s < -3s + 3s, i.e. 4s < 0. Since 4 is positive, we can
divide the inequality by 4 to obtain s < 0. Hence, any
negative real number satisfies the original equality s < -3s.

Answer 2

First of all, s must be negative.
If s = 1, then 1 < -3, which is false.
At 0, 0 < 0, which is also false.
If s = -1, then -1 < 3, which is true.

If you subtract s from both sides you get
s -s < -3s - s
or 0 < -4s

Multiply by -1/4 on both sides (and remember to change the direction of the sign when you do it).

-1/4 * 0 > -1/4 * -4 * s
0 > s

Answer 3

Are you sure the equality is like that. Dividing by s on both sides yieds 1<-3 which is obviously not right

Answer 4

Any negative number will make that inequality true.

Answer 5

it actually equals s<0