In the quadratic equation x^2-3x=10 what is the only positive solution?

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In the quadratic equation x^2-3x=10 what is the only positive solution?

2007-02-25 06:22:29 · 5 answers · asked by d m 1 in Science & Mathematics ➔ Mathematics

5 answers

Its roots are (3 +- Sqrt[9 + 40])/2 = (3 +- 7)/2 = 5 or -2,
so 5 is the answer.

2007-02-25 06:27:08 · answer #1 · answered by I know some math 4 · 0⤊ 0⤋

x=5

2007-02-25 14:27:31 · answer #2 · answered by raj 7 · 0⤊ 0⤋

x^2-3x-10=0

Factor need 2 numbers that multiply to -10..
-5,2 -2,5 -10,1 -1,10

They need to add to -3

-5 and 2

(x-5)(x+2) = 0
the only positive solution is x = 5

2007-02-25 14:28:51 · answer #3 · answered by radne0 5 · 0⤊ 0⤋

xÂ² - 3x - 10 = 0
(x - 5).(x + 2) = 0
x = 5, x = - 2
Positive solution is x = 5

2007-02-25 14:39:18 · answer #4 · answered by Como 7 · 0⤊ 0⤋

there are two roots x=0 and x=3.The only positive is x= 3

2007-02-25 14:27:03 · answer #5 · answered by santmann2002 7 · 0⤊ 0⤋