work out...
(3-rt.2)(2=3rt.2)all divided by rt.8
give your answer in its simplist form
i got 7/rt.8 but i really think its wrong
2007-02-25 05:49:22 · 4 answers · asked by jenny 1 in Science & Mathematics ➔ Mathematics
sorry yes it isnt alegerbra... and i didnt mean = i meant + sorry guys
2007-02-25 07:59:47 · update #1
I will use sqrt(x) for the square root of x.
Your question (without the typo, suppose you meant + instead of =) is to evaluate the expression below:
(3 - sqrt(2)) * (2 + 3*sqrt(2)) / sqrt(8) =
(6 + 9*sqrt(2) - 2*sqrt(2) - 3*sqrt(2)^2) / (2*sqrt(2)) =
(6 + 7*sqrt(2) - 6) / (2*sqrt(2)) =
7*sqrt(2) / 2*sqrt(2) =
7/2
2007-02-25 06:03:00 · answer #1 · answered by jcastro 6 · 0⤊ 0⤋
(3 - \/2)(2 + 3\/2)all divided by \/8 =
Transforming in the same radical \/2:
[3(2 + 3\/2) - \/2(2 + 3\/2)] : 2\/2 =
(6 + 9\/2) - (2\/2 + 3\/2²) : 2\/2 =
(6 + 9\/2 - 2\/2 + 3*2) : 2\/2 =
(6 - 6 + 7\/2) : 2\/2 =
7\/2 : 2\/2 = 7/2
::
2007-02-25 15:13:31 · answer #2 · answered by aeiou 7 · 0⤊ 0⤋
Can you make this easier to read? This has nothing to do with algebra.
2007-02-25 05:52:27 · answer #3 · answered by Daniel M 2 · 0⤊ 0⤋
(3-rt2)(2+3rt2)/2rt2
=6+9rt2-2rt2-6/2rt2
=(7/2)
so7/rt8 is wrong
2007-02-25 05:52:53 · answer #4 · answered by raj 7 · 0⤊ 0⤋