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2007-02-25 05:33:52 · 3 answers · asked by jdk1961 2 in Science & Mathematics Mathematics

3 answers

Area
r^2[A - sin(A)]/2
r^2arccos([r - h]/r) - (r - h)sqrt(2rh - h^2)
r^2arccos(d/r) - dsqrt(r^2 - d^2)

whereas i'm using A to stand for theta

if you go to the site below, it will tell you how to get whatever you are missing.

2007-02-25 06:08:42 · answer #1 · answered by Sherman81 6 · 0 0

well for a whole circle the formula is pi x radius^2

so for a partial circle you find that and divide by 2 if you have a half circle, divide by 3 if you have third of a circle, etc...

2007-02-25 13:42:19 · answer #2 · answered by meeepaulinee 2 · 0 0

Is the partial circle divided by a chord? or sliced like a pie?

2007-02-25 13:42:11 · answer #3 · answered by rscanner 6 · 0 0

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