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2007-02-25 05:10:35 · 12 answers · asked by Anonymous in Science & Mathematics Mathematics

12 answers

x(2x^2-9x+10)
(2x-5)(x-2)

2007-02-25 05:14:19 · answer #1 · answered by Anonymous · 0 1

the first thing you want to do when factoring is look to see if there is a common factor is everything listed.
when you look you will see that they all have 1 x in them.
factor out the common factor
x(2x^2 - 9x + 10)

now look at what is inside the parenthesis and start to factor by making 2 binomials. look at the first term. It can only be factored this way
x(2x )(x )

Now look at the sign on the last number. It is a positive (+). That means that both the signs are the same. look back to the sign on the second number. It is a negative (-). They are both negative.
x(2x - )(x - )

Now look at the last number. It is 10. What 2 numbers when multiplied together give you 10. It is either 10 and 1 or 5 and 2. Test them so that when you foil the problem you end up with a 9 in the second spot.

x(2x - 5)(x - 2)

There you go.

2007-02-25 05:23:47 · answer #2 · answered by SheTigger2 4 · 0 0

2x^3-px^2+10x

First take out the gcf (x). Now you have:

x(2x^2-9x+10)

Now you can factor the trinomial

x (x-2) (2x-5)

There is your answer : )

x (x-2) (2x-5)

2007-02-25 05:20:24 · answer #3 · answered by Mysara e 2 · 0 0

a million. 3(x-8)(x+8) 2. 2(9x+2)(9x-2) 3.3(x-2)(x-12) 4. 3(x-7)(x-3) 5.(4x-a million)(4x-a million) 6.3(x-12)(x-2) 7.4(x-8)(x+10) 8. 2(x+2)(x+3) 9. 3(x+2)(x-a million) 10. (x+a million)(x-a million)(2x+3) 11.3(x+a million)(x+3)(x-3) 12. (x-2)(x+2)(x^2+4) 13. (y-3)(y+3)(y^2+9) 14. 2(2x+3)(2x-3) 15. 2(x-4)(x-4)

2016-10-16 11:19:44 · answer #4 · answered by Anonymous · 0 0

take out x
x(2x^2 - 9x + 10)

look for two numbers that multiply to 20 and add up to -9
-4 and -5

2x^2 - 4x - 5x + 10

factor by groups
(2x^2 - 4x ) + (-5x + 10)
2x(x - 2) + -5(x-2)

x (2x-5) (x-2)

hope this helps

2007-02-25 05:15:58 · answer #5 · answered by      7 · 0 0

Break the mid term in two

2x^3-4x^2-5x^2+10x

Take 2x as common from first two terms and -5 as common
from second pair.

Now when you divide 2x^3-4x^2 by 2x you will get x^2-2x
Now when you divide 5x^2-10x by -5 you will get x^2-2x

=2x(x^2-2x)-5(x^2-2x)

Now take (x^2-2x) as common from the remaining two terms.
I think that the step next does not need clearification.

(x^2-2x) ( 2x-5)

Hope to answer the question upto satisfaction.
MFQ

2007-02-25 05:27:11 · answer #6 · answered by Muhammad Faraz Quadri 2 · 0 1

2x^3 - 9x^2 + 10x
x(2x^2 - 9x + 10)
x(x - 2)(2x - 5)

2007-02-25 06:29:45 · answer #7 · answered by Sherman81 6 · 0 0

x(2x^2-9x+10)

x (2x-5)(x-2)

2007-02-25 05:26:47 · answer #8 · answered by Dave aka Spider Monkey 7 · 0 0

take out x
x(2x^2-9x+10)
x(2x-5)(x-2)

2007-02-25 05:24:54 · answer #9 · answered by adriantheace 4 · 0 0

x(2x-5)(x-2)

2007-02-25 05:18:48 · answer #10 · answered by Jeffrey W 3 · 0 0

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