solve the equation (84)?

Question

3 + radical x^2 - 8x = 0

Answer 1

By radical x^2, you mean the square root of x squared, right? That equals x, so:

3+x-8x=0
combine the x terms
3-7x=0
Add 7x to both sides:
3=7x
Divide by 7
3/7=x

Answer 2

radical x^2 = 8x-3 As rad x^2 has no sign before it,it is positive or 0
so 8x-3>=0 x>=3/8
Squaring both sides x^2= 64x^2 -48x+9 so 63x^2-48x+9=0

x=(( 48+-sqrt(2304-2268))/126 =( 48+-6) 126

x= 54/126= 3/7 >3/8 and x= 42/126 = 7/21 <3/8 and is NOT sol.

so the only solution is x= 3/7