solve
6x-2y=33
4x+3y=9
2007-02-25 04:09:44 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Equation 1 :- 6x - 2y = 33
Equation 2 :- 4x + 3y = 9
Multiplying eqn.1 by 3 and eqn.2 by 2 to make the y's equal so that equals,
18x - 6y = 99
8x + 6y = 18
The 6y's get cancelled and,
we get 26x = 117
so that makes x = 4.5
Now, multiply value of "x" with equation 1
We get,
6(4.5) - 2y = 33
27 - 2y = 33
-2y = 33 - 27
-2y = 6
Therefore, y = 6/-2
and y = -3
Answer => x = 4.5 and y = -3
2007-02-25 04:25:45 · answer #1 · answered by Anonymous · 1⤊ 0⤋
multiply top by 2 and bottom by 3
12 x - 4 y = 66
12 x + 9 y = 27
subtract
13 y = -39
so y = -13
substutute back
12 x + 52 = 66 so 12 x = 14 so x = 7/6
2007-02-25 04:20:43 · answer #2 · answered by hustolemyname 6 · 0⤊ 0⤋
6x-2y=33
4x+3y=9
Multiply the first equation by -4 and the second equation by 6:
-24x+8y=-132
24x+18y=54
==========
26y=-78
y=-3
6x-2(-3)=33
6x+6=33
6x=27
x=27/6=9/2
The solution set is (9/2,-3)
Check:
6(9/2)-2(-3)=33
27+6=33
33=33
4(9/2)+3(-3)=9
18-9=9
9=9
I hope this helps!
2007-02-25 04:24:03 · answer #3 · answered by Anonymous · 0⤊ 0⤋
solve for x or y in one equation and then substitute it in the other equations.
2007-02-25 04:18:55 · answer #4 · answered by summerlovin9590 2 · 0⤊ 0⤋