Somebody please give the answer to this asap!!?

Question

Xenya, Yolanda and Zoë are having a race. Yolanda is 1.2 times as likely to win as Xenya, and Zoë is 2.3 times as likely to win as Yolanda. What is the probability that Yolanda wins?

Answer 1

The probability would be 100% if she would just do a Tonya Harding on both Xenya and Zoe. She should take charge and do it.

(Put that in your homework, I guarantee an A for creative thinking.)

Long Live Jambi

Answer 2

Das Kaushik shows the right method, but he has worked out the probability of X - which is Xenya.

Use the same method of substitution, but find P(Y) which is the probability of Yolanda winning.

Answer 3

Y = 1.2 X
Z = 2.3 Y

Thus Z = 2.3x1.2 X; i.e. Z = 2.76 X

X+Y+Z = (1+1.2+2.76) X = 4.96X

Probability is therefore 1.2/4.96 which is approx 0.241935

Therefore the percentage probability is approx 24.1935 percent.

I hope this helps.

Answer 4

the answer is 3 to 1

Answer 5

X+Y+Z=100

Y=1.2X
Z=2.3Y

Y/1.2+Y+2.3Y=100 Y=24.2%

Answer 6

let X be the smallest, then Y= 1,2X and more on Z=2,3Y= 2,3(1,2X)=2,76X
=> X+1,2X+2,76X=1
=> 4,96X=1
=> X=1/4,96
=> Y=1,2/4,96
=> Y=0,2419354...
=> Y=24 %

Answer 7

I keep getting 24.19% or 0.2419 probability but I am probably doing it wrong.

based on:
xenya + yolanda + zoe = 100%

x + 1.2x + 2.3(1.2x) = 100 ??????

Answer 8

I have just worked this out, and it seems DAS_KAUSHIK_CAL has done it exactly the same way- so just follow him. He has omitted the final calculation which comes out as

24.19%

That is a guarantee, I am a Mathematics research student, I should know.

Answer 9

Lets put symbols to names
Xenya = X, Yolanda = Y, Z = Zoä
We are given
P(Y) = 1.2*P(X)
P(Z) = 2.3*P(Y)
We know by definition,
P(X)+P(Y)+P(Z) =1
i.e., P(X)+1.2*P(X)+2.3*P(Z)=1
i.e,, 2.2*P(X)+2.3*1.2*P(X)=1
i.e., 2.2*P(X)+2.76*P(X)=1
i.e., 4.96*P(X)=1
i.e., P(X)=1/4.96
Hope this answers your question

Answer 10

Whoa. Ask a bookie.