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For nЄN,

[2n-18]/[(n^2)-8n+8] < 1

I think this has to be done with induction? I'm not sure how to do it though. Could someone help?

2007-02-25 03:58:10 · 3 answers · asked by namesake 1 in Science & Mathematics Mathematics

3 answers

it is false at n=2

(2*2-18)/(2^2 - 8*2 + 8)
= (4-18)/(4-16+8)
= -14 / -4
= 7/2 > 1

2007-02-25 04:30:16 · answer #1 · answered by Scott R 6 · 2 0

Even if it were true, you probably wouldn't prove it by induction. You'd just look at the function defined by the left hand side defined over the range, say, [1, infinity), and as a last step check whether restricting the range to the natural numbers made any difference.

2007-02-25 09:04:31 · answer #2 · answered by Curt Monash 7 · 0 0

i'm assuming that R denotes the set of all real numbers. it rather is particularly ordinary to make a counterexample. The function f(x) = x is non-provide up, via fact that all polynomial purposes are non-provide up, yet this function is obviously unbounded on R. So the fact is fake.

2016-11-25 22:22:05 · answer #3 · answered by Anonymous · 0 0

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