im trying to work out what 10 and then the little -5 which is a cube number. Do i go 10x10x10x10x10 or is it different because a - is stuck infront of the 5 ?
2007-02-25 03:53:37 · 6 answers · asked by TurionJM 1 in Science & Mathematics ➔ Mathematics
Yes its different, x^y when y is negative is equal to 1/x^-y
also, (10^-5)^3 simplifies to 10^-15 = 1/10^15
do you see why?
take (2^2)^3 = 2^6 for example, you have two groups of two and three groups of those or 6 groups all togeter.
theorems:
(x^y)^z=x^(yz)
x^y * x^z = x^(y+z)
2007-02-25 04:00:56 · answer #1 · answered by Scooter_MacGyver 3 · 0⤊ 0⤋
What you have is actually a "negative exponent". It means that instead of 10x10x10x10x10, you are dealing with 1/10x1/10x1/10x1/10x1/10. When you have a negative exponent it means the "base"-in this case 10- is on the wrong side of the fraction line. All you have to do is invert it.
2007-02-25 12:22:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋
It is not called a "cube". A cube is the power of three.
10^-5 = 1/(10^5) = .000001 [count the # of zeros]
2007-02-25 12:04:08 · answer #3 · answered by Randy G 7 · 0⤊ 0⤋
You take the difference of the exponents. So it will be 10 to the -2 which will be .01.
2007-02-25 11:58:04 · answer #4 · answered by cbay8882 2 · 0⤊ 0⤋
10^-5
This would be an inverse, so the problem would be set up like this:
1/10^5=1/100,000
I hope this helps!
2007-02-25 12:04:11 · answer #5 · answered by Anonymous · 0⤊ 0⤋
it means
-10x-10x-10x-10x-10
so it equals 0.00001
2007-02-25 11:59:22 · answer #6 · answered by mackenzie 2 · 0⤊ 0⤋