The Great Pyramid of Cheops has a square base with sides 755 ft long. The original height was 481 ft, but the top part of the pyramid, which was 31 ft in height, has been destroyed.
2007-02-25 03:34:47 · 2 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Americagirl's answer would find the pyramid's volume remaining if the entire pyramid shrunk proportionally, rather than just lopping off the top of the pyramid. You need to find the full pyramid size, and then find the size of the 31 ft tall pyramid that was destroyed.
Area of pyramid: V=1/3Bh
Full pyramid: V = 1/3 (755^2)(481) = 91394008 ft^3
Lost pyramid: First you need the side of a base side. The base side will be proportional to the height, so:
full height / full side = lost height / lost side
481 / 755 = 31 / x
1 / x = 481 / 755 * 31
x = 755 * 31 / 481 = 48.66
Base = base side^2 = 2367.8
Lost Pyramid V = 1/3bh = 1/3(2367.8)(48.66) = 38406 ft^3
Find the percentage of the lost portion to full pyramid:
38406 ft^3 / 91394008 ft^3 = .000420 = .042% of the pyramid was lost.
100 - .042% = 99.958% of the pyramid remains.
2007-02-28 06:00:00 · answer #1 · answered by ³√carthagebrujah 6 · 0⤊ 0⤋
about 94% you find the volume of the originial pyramid which was about 91394008 (V=1/3Bh), then you find the volume of the pyramid with the new height (subtract 41 from orginal height) you get about 85503750, you put the new number of the orginal number and you can either divide or set it up as a proportion with its equal be x over 100
2007-02-25 11:44:52 · answer #2 · answered by americagirl2000 1 · 0⤊ 0⤋