factorise (x+y)^2 - 3(x+y)
i got x^2+y^2+2xy-3x+3y ... but im not sure if its right
2007-02-25 03:33:26 · 7 answers · asked by jenny 1 in Science & Mathematics ➔ Mathematics
no. if you look at it this way (x+y)^2 + (-3)(x+y)
x^2+y^2+2xy-3x-3y
the negative goes with the 3
2007-02-25 03:41:28 · answer #1 · answered by srena 5 · 0⤊ 0⤋
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2016-10-16 11:12:44 · answer #2 · answered by scafuri 4 · 0⤊ 0⤋
You expanded rather that factorised. The factors are (x + y) and (x + y - 3).
2007-02-25 04:00:12 · answer #3 · answered by Anonymous · 0⤊ 0⤋
you expanded but didn't factorise.
= (x+y) ( (x+y) - 3 ) = (x+y)(x+y-3)
2007-02-25 03:37:00 · answer #4 · answered by hustolemyname 6 · 0⤊ 0⤋
"Factorise" suggests that a common factor be found.
The common factor in this case is (x + y)
(x + y).(x + y) - 3(x + y)
(x + y) [(x + y) - 3]
(x + y). (x + y - 3) ]
2007-02-25 05:05:34 · answer #5 · answered by Como 7 · 0⤊ 0⤋
(x+y)^2 - 3(x+y)
=(x+y)[(x+y)-3]
=x^2+y^2+2xy-3x-3y
i hope that this helps
2007-02-25 03:47:57 · answer #6 · answered by Anonymous · 0⤊ 0⤋
take out the +2xy, and ur right i think
2007-02-25 04:42:07 · answer #7 · answered by dancin' chick 2 · 0⤊ 0⤋