If the length of a pendulum is cut in half, by what factor does its period change?

Answer 1

The period of the pendulum is given by T= 2pi(L/g)
as by equation,..L is directly proportional to T
SO,...if L changes to be L/2.....then....T will become half too
also note: if T decreases...means that the pendelum becomes FASTER....NOT slower

Answer 2

Hmmm... for a simple pendulum, the period is given by:

Period = 2*pi*(L/g)^0.5 , that is, 2*pi times the square root of (L/g) ;

where L is the pendulum length.

Therefore the period is proportional to the square root of L, the length of the pendulum. If you halve the pendulum length, the square root of 0.5 is approx 0.707. So the period is reduced to about 70.7% of original. So a 60 second cycle would be reduced to a little of 42 seconds. (numerical numbers are estimates).

Answer 3

The shorter the length the shorter the period
http://online.cctt.org/physicslab/content/Phy1HON/lessonnotes/pendulums/period.asp

go to this link and do the math