2007-02-25 00:23:51 · 3 answers · asked by Apollos 1 in Science & Mathematics ➔ Chemistry
i don't get what the book said that's why i'm asking..i already answered everythin else
2007-02-25 00:31:36 · update #1
If you think about how alkanes are structured, especially for the straight chains, you will always have a -CH3 group on each end with -CH2- groups in the middle. Two ends = two extra hydrogens. Even when you have branched alkanes, you will then be substituting an alkyl group for one of the hydrogens on a -CH2- group, so the formula will still hold.
Once again, it appears some people don't know how to instruct without being condescending. You don't get to Level 7 by being an arrogant schmuck.
2007-02-25 01:36:07 · answer #1 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋
Start drawing the alkanes out and you will see why.
Try
propane n=3
pentane n=5
octane n= 8
count up the hydrogens and carbons do they match the formula?
well there you go . . . or you can waste your time counting up the carbons and hydrogens on the test when you could just use this fundamental fact
2007-02-25 00:39:52 · answer #2 · answered by bourgoise_10o 5 · 0⤊ 0⤋
gosh, another school work problem that the poster is to lazy to work out on their own.
Read the book !
2007-02-25 00:27:01 · answer #3 · answered by Anonymous · 0⤊ 2⤋